find the 9th term in the expansion of (2a+x)10
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There is one mid term, i.e., 10/2 + 1
T6= T5+1= 10C5.(x)10-5 .(9y)5
=14880348. x5.y5
T6= T5+1= 10C5.(x)10-5 .(9y)5
=14880348. x5.y5
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