Question

find the 9th term of an AP from the end of the AP : -5, -5/2 , 0, 5/2 . . . . . .

Answer 1

Answer:

a=-5

d =- 5/2+5 = 5/2

a9= a +(n-1)d

. -5 +8x5/2

=-5+20 = 15. Ans