Question

find the 9th term of an arithmetic progression:- 3/4,6/4,9/4,12/4,.....​

Answer 1

Answer:

a9 want to find right

then

a=3/4;d=a2-a1

d=6/4-3/4=3/4

n=9

the a9=?

a9=a+(n-1)d

a9=a+8d

a9=3/4+8(3/4)

a9=3/4+6

a9=3+24/4

therefore a9=27/4

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Answer 2

Answer:

27/4

Step-by-step explanation:

1st term = 3/4

2nd term = 6/4

3th term = 9/4

4th term = 12/4

rule: the denominator is always  4 and the numerator is n multiplied by 3

n being the term number

9th term = 9*3/4

27/4