Question

Find the 9th term of AP 3, 2 ½, 2,....​

Answer 1

Answer:

t1 = a = 3

t2 = a+d

2½ = 3 + d

2½ - 3 = d

d = -½

tn = a + (n-1)d

t9 = a +(9-1)d

t9 = 3 + 8 × (-½)

t9 = 3 - 4

t9 = -1

Step-by-step explanation:

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