find the 9th term of the geometric sequence 15,45,135,405,....
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Answered by
2
The term is the term before it multiplied by three.
3is known as the common ratio.
Answered by
1
Step-by-step explanation:
t1=15
t2=45
t3=135
D=T2-T1
=45-15
D =30
T9=A+(N-1)D
=15+(9-1)30
=15+8(30)
=15+240
T9 =255
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