find the 9th term of the sequence 1,√2,2
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Answered by
4
Answer:
16
Step-by-step explanation:
Every term is multiplied by √2
NeelamG:
n=9,a=1, r= √2
so, a9 = 1×√2^(9-1)
a9= (√2)^8 = 16
Answered by
1
the answer is 16 because every time it multiple by √2
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