Find the 9th term of the series: √2, 4√2, 9√2, .......
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81 root 2
In the 1st term root2 is multiplied by square of 1
In the second term root2 is multiplied by square of 2 , i.e 4
In the third term root2 is multiplied by square of 3 , i.e 9
Similarly in the n th term root 2 should be multiplied by square of 9
So 9th term = root2 x 9square
So 9th term = 81 root2
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In the 1st term root2 is multiplied by square of 1
In the second term root2 is multiplied by square of 2 , i.e 4
In the third term root2 is multiplied by square of 3 , i.e 9
Similarly in the n th term root 2 should be multiplied by square of 9
So 9th term = root2 x 9square
So 9th term = 81 root2
Hope it helped you, please thank this answer and mark this answer as brainiest answer also it helps us to be motivated to help people like you and me
Answered by
1
Answer:
81√2
Step-by-step explanation:
Series of terms is
√2, 4√2, 9√2, 16√2, 25√2, 36√2, 49√2, 64√2, 81√2, 100√2.......
hope u understand
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