Question

find the a b c d value?​

Answer 1

Answer:

Sorry don't know mate

Step-by-step explanation:

Please follow

Answer 2

Step-by-step explanation:

quadrilateral ABCD us a parallelogram

therefore in ∆DCB ,

Angle BDC+angle C+ angle DBC=180°---------(sum of all angles of ∆)

therefore 3a+7a+2a=180°

I.e. 12a=180

therefore a= 15°

Now, side AB||side DC and seg BD is transversal,

therefore angle BDC= angle ABD----------(alternate angles)

i.e. 3a=b

=3×15=b

therefore b=45°

also, angle ADB=angle DBC---------(alternate angles)

i.e. d° = 2a°

d= 2×15

i.e. d= 30°

Now, in ∆ ADB,

angle A+ angle ADB+ angle ABD=180°--------(sum of all angles of∆)

therefore c°+d°+b°=180°

i.e. c°+30°+45°=180°

= c°+75=180

therefore c= 105°