Question

find the A.P whose first term a=5 and common difference d=6​

Answer 1

AP= a, a+d,a+2d,a+3d,..........

given :

a=5

d=6

t1=a=5

t2=a+d =5+6=11

t3=a+2d=5+6(2)=5+12=17

t4=a+3d=5+6(3)=5+18=23

Therefore, A.P=5,11,17,23...