Question

find the A.P whose first term a=5 and common difference d=6
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Answer 1

Answer:

5

Step-by-step explanation:

a=5

d=6

n=1

it putt into the formula

an=a+(n-1) ×d

an=5+(1-1)×6

an=5+0×6

an=5

Answer 2

Answer:

Step-by-step explanation:

Concept:

The concept of sequence will help to solve this question.

The difference between any two consecutive integers in an arithmetic progression (AP) sequence of numbers is always the same amount. It also goes by the name Arithmetic Sequence. For instance, the natural number sequence $1, 2, 3, 4, 5, 6,...$ is an example of an arithmetic progression. It has a common difference of $1$ between two succeeding terms (let's say $1$ and $2$). $(2 -1)$. We can see that the common difference between two subsequent words will be equal to $2$ in both the case of odd and even numbers.

Given:

In this sequence, first term$(a)$ is $5$ and common difference $(d)$ is $6$ .

To find:

We need to find the arithmetic progression by using above values.

Solution:

The formula of A.P is $a_{n}=a+(n-1)\times d$ .

Where $a_{n}$ is the value of  $n^{th}$ term that is $5$ , $a$ is the value of first term whose value is $5$ , $n$ is $n^{th}$ term and $d$ is $6$ which is the difference .

Put the value in the above equation.

$5+(1-1)\times 6=5$

Therefore, the A.p is $5$ .

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