Question

Find the A.P. whose sum of 'n' terms is is 2n2+2

Answer 1

Sum of n terms = 2n² + 2
S1 = Sum of the series with one term = 2(1)² + 2 = 4
S2 = Sum of the series with two terms = 2(2)² + 2 = 10
S3 = Sum of the series with three terms = 2(3)² + 2 = 20

T1 = S2 - S1 = 10 - 4 = 6
T2 = S3 - S2 = 20 - 10 = 10
Common difference = t2 - t1 = 10 - 6 = 4
A.P. = 6, (6 + 4), (6 + 8), (6 + 12)......

Answer 2

Answer:

Sum of n terms = 2n² + 2

S1 = Sum of the series with one term = 2(1)² + 2 = 4

S2 = Sum of the series with two terms = 2(2)² + 2 = 10

S3 = Sum of the series with three terms = 2(3)² + 2 = 20

a1 = S2 - S1 = 10 - 4 = 6

a2 = S3 - S2 = 20 - 10 = 10

Common difference = a2 - a1 = 10 - 6 = 4

A.P. = 6, (6 + 4), (6 + 8), (6 + 12)

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