Question

Find the 'a' value distance between (a,2) and (3,4) is 2√2.

Answer 1

$distance \: formula \\ \\ distance \: = \sqrt{( x_{2} - x_{1})^{2} + ( y_{2} - y_{1}) ^{2} }$

Applying distance formula :-

$2 \sqrt{2} = \sqrt{(3 - a) ^{2} + {(4 - 2)}^{2} } \\ \\ {(2 \sqrt{2} )}^{2} = {(3 - a)}^{2} + {2}^{2} \\ \\ 8 = {(3 - a)}^{2} + 4 \\ \\ 8 - 4 = {(3 - a)}^{2} \\ \\ 4 = (3 - a)^{2} \\ \\ \sqrt{4} = 3 - a$

±2 = 3 - a

a = 3 ± 2

a = (3 + 2) or (3 - 2)

a =5 or 1



I hope this will help you


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