Question

find the above answer to the question in the attachment.



best answer will be marked as brainliest.​

Answer 1

Answer:

Given,

PR + QR= 50 cm

Let QR= $x$

PR + QR= 50 cm

PR= 50 - QR

PR= 50 - $x$

In right triangle PQR,

Using pythagoras theorem,

(hypotenuse)² = (height)²+ (Base)²

PR² = PQ²  + PR²

(50-$x$)² = 40² +

(50²) + $x$² - 2 × 50 × x = 1600 ×

2500 + $x$² - 100x = 1600 ×

2500 + $x$² - 100x - 1600 ×

$x$² -

-100$x$ + 900 = 0

-100$x$ = -900

$x=-900/-100$

$x$ = 9 cm

$Hence, QR=x=9$

$PR=25-x$

       = 25 - 9

       = 16 cm

i)sin P

sin P= QR/PR

sin P= 9/16

ii) cos P

cos P= PQ/PR

cos P= 40/16

iii) tan R

tan R= PQ/OR

tan R= 40/9

Figure is given below:

It took a lot of time to solve it as I was making it understandable. :) Hope it helps you!

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