Question

Find the abscissa of the point which divides the line joining points (0,4) & (0,8) internally in the ratio of 3:1.

Answer 1

SOLUTION

Using formula of internal division;

$= > </u><u>[</u><u> \frac{m1x2 + m2x1}{m1 + m2} \: </u><u>,</u><u> \frac{m1y2 + m2y1}{m1 + m2} </u><u>]</u><u> \\ \\ = > </u><u>[</u><u> \frac{3(0) + 1(0)}{3 + 1} </u><u>,</u><u> \: \frac{3(8) + 1(4)}{3 + 1} </u><u>]</u><u> \\ \\ = > </u><u>[</u><u>\frac{0}{4} \:</u><u>,</u><u> \frac{24 + 4}{4} </u><u>]</u><u> \\ \\ = > </u><u>[</u><u> \frac{0}{4} \: </u><u>,</u><u> \frac{28}{4} </u><u>]</u><u> \\ \\ = > (0 \: </u><u>,</u><u>7) \\ \\ </u><u>A</u><u>bscissa \: of \: x = 0 \: \: \: \: \: \: </u><u>[</u><u>A</u><u>nswer</u><u>]</u><u>$

Hope it helps ☺️