Question

Find the abscissae of points whose ordinate is
4 and which are at a distance of 5 units
from (7,8)?​

Answer 1

Answer:

DISTANCE FORMULA -

$\sqrt({x2 - x1 )+ } (y2 - y1)$

$x1 = x \\ y1 = 4 \\ \\x2 = 7 \\ y2 = 8$

Step-by-step explanation:

√( X - 7)^2 + ( 8-4 ) ^4 = 5

√( x - 7 ) ^2 + 16 = 25

( x- 7)^2 = 25 - 16 = 9

√X - 7 = +3 ; x -7 = -3 x

=10 OR -4