Question

find the absolute error and relative error for 0.56,0.75,0.62,0.45,0.38
please answer it correctly!​

Answer 1

Explanation:

The diameter of a wire as measured by a screw gauge was found to be 1.002 cm, 1.004 cm and 1.006 cm. The absolute error in the readings will be:

Solution:

Mean=

3

1.002+1.004+1.006

=1.004cm

Hence, absolute errors

Δa

1

=1.002−1.004 =0.002cm

Δa

3

=1.004−1.004 =0.000cm

Δa

3

=1.006−1.004 =0.002cm