Question

Find the absolute error in the parallel combination of R1and R2.​

Answer 1

For two resistor R

1

and R

2

, connected in parallel, find the relative error in their equivalent resistance, if R

1

=(50±2)Ω and R

2

=(100±3)Ω

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ANSWER

Two resistors, R

1

andR

2

are connected in parallel.

We know,

R

e

1

=

R

1

1

+

R

2

1

Then R

e

=

R

1

+R

2

R

1

R

2

=

50+100

50×100

=

150

5000

=

3

100

Now, Parallel Connection error:

=

(R

1

+R

2

)

2

R

1

2

(dB)+R

2

2

(dA)

=

150

2

50

2

(3)+100

2

(2)

=

150×150

7500+20000

=

9

11

Relative Error =

(100/3)

(11/9)

=0.03666