Question

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = x/(x^2 + 25), [0, 6].

Answer 1

Now evaluate at the endpoints of the interval. f(0) = 0 and f(9) ... Thus 0 is the absolute minimum (since f(0) is less than ... f' = (x^2 + 25 - 2x^2) / (x^4 + 50x^2  ...

Answer 2

Add and subtract 2x to the expression so that it becomes (x^2+2x)e^-x + (1-2x)e^-x.