Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals:
f (x) = x³, x ∈ [–2, 2]
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maximum and minimum values of a function f given by f(x)=2x^3- 15 x^2+36 x+1 on the interval [1,\ 5] .
pls Mark brainliast
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Answer:
-8 and 8
Step-by-step explanation:
f(x) = x³
f'(x) = 3x², the first derivative is always positive. Hence f(x) is ever increasing.
Therefore minima in [-2,2] is f(-2) = -8
maxima in [-2,2] is f(2) = 8
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