Question

find the ac resistance of semiconductor diode having a forward bias of 200 mv and reverse saturation current of 1 microampere at room temperature​

Answer 1

Answer:the ac resistance of semiconductor diode having a forward bias of 200 mv and reverse saturation current of 1 microampere at room temperature​ is 91.32 ohms

Explanation:  

We know that Diode current is given by Shockley's equation,

Id=Is[e^(\frac{Vd}{n*Vt})-1]

Where Id is the forward current,

Is: reverse saturation current

Vd is the voltage applied across diode

Vt: thermal voltage i.e. 26mV at room temperature

Id=10^-6[e^((200*10^-3)/(1*26*10^-3))-1]

Id=2.19mA

Hence the AC resistance is= 200/2.19=91.32 ohms