Question

Find the acceleration at time t of the particle which moves according to the following law
in a straight line
X = (t + 1)

Answer 1

Answer:

Correct Option is d

Step-by-step explanation:

hope its help

Answer 2

Answer: d) 2/(t+1)^3

Step-by-step explanation:

we know tha acceleration at any time t is = d^2x/dx^2

Here give, x = 1/(t+1)

then, dx/dt = -1/(t+1)^2

Again, d^2x/dx^2 = 2/(t+1)^3