Question

find the acceleration due to gravity at die surface of the earth​

Answer 1

Answer:

Depending on the location, an object at the surface of Earth falls with an acceleration between 9.76 and 9.83 m/s2 (32.0 and 32.3 ft/s2).

Answer 2

Answer:

Explanation:

F=GMm÷r²

we know that f=ma

so,

ma=GMm÷r²

a=GM÷r²

G=6.67×10∧-11

M=6×10∧24

r=6.4×10∧6

subs. all the values we get,

a=9.8 m/s∧2