Question

Find the acceleration due to gravity on the surface of Jupiter using the data given below;(Mass of Jupiter: M = 1.9 x 10^27 kg,the radius of Jupiter = R = 7 x 10^7 m​

Answer 1

Answer:

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Explanation:

$to \: find = \\ gravitational \: acceleration \: on \: jupiter \: (g)\\ \\ given = \\ on \: surface \: of \: jupiter \\ mass \: of \: jupiter \: (M) = 1.9 \times 10 {}^{27} \: kg \\ radius \: of \: jupiter \: ( R) = 7 \times 10 {}^{7} \: m \\ \\ \: G = 6.67 \times 10 {}^{ - 11} \: \frac{Nm {}^{2} }{kg {}^{2} } \\ \\ so \: we \: know \: that \\ \\ g = \frac{GM}{R {}^{2} } \\ \\ = \frac{6.67 \times 10 {}^{ - 11 } \times 1.9 \times 10 {}^{27} }{(7 \times 10 {}^{7}) {}^{2} } \\ \\ = \frac{6.67 \times 1.9 \times 10 {}^{ - 11 + 27} }{49 \times 10 {}^{14} } \\ \\ = \frac{6.67 \times 1.9 \times 10 {}^{16 {} } \times 10 {}^{ - 14} }{49} \\ \\ = \frac{12.673 \times 10 {}^{16 - 14} }{49} \\ \\ = 0.2586 \times 10 {}^{2} \\ \\ = 0.2586 \times 100 \\ \\ g = 25.86 \: \: \frac{m}{s {}^{2} }$