Question

Find the acceleration if the average time is 1 second

Answer 1

Given: s = 1/5*t^3 + 5t^2 - 10t + 1

velocity v = ds/dt = 3/5*t^2 + 10t – 10

after 1 second, v = 3/5 = 0.6m/s

acceleration a = dv/dt = 6/5t + 10

after 1 second, a = 11.2m/s^2

when v = 0, 0.6t^2 + 10t – 10 = 0 solving, t = 0.943s

at t = 0.943, a = 6/5(0.943) + 10 = 11.132m/s^2