Find the acceleration (m/s) of Cheetah if it acquires the velocity of 135 kmph with in 2s
after the start
a) 25/4
b) 35/4
c) 55/4
d) 75/4
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Answers
Answered by
113
Solution :-
By the given information ,
- Velocity = 135 km/h
- Time taken = 2s
Here the given final velocity is in km/h , so we have to convert into SI units (m/s) .
♦ 135 km/h × 5/18 = Velocity in m/s
♦ 75/2 = Velocity in m/s
♦ Velocity in m/s = 37.5
Now , as we know that
Acceleration = Velocity/Time
⇒ Acceleration = 37.5/2
⇒ Acceleration = (75/2)/2
⇒ Acceleration = 75/2 × 1/2
⇒ Acceleration = 75/4
Hence , acceleration of the cheetah = 75/4 m/s²
Answered by
77
Answer:
Given :-
Velocity = 135 km/h
Time = 2 sec
To Find :-
Acceleration (m/s)
Solution :-
Velocity in m/s
135 × 5/18
= 45 × 5/6
= 225/6
= 75/2
Now,
A = v/t
Where
A = Acceleration
v = velocity
t = time
A = (75/2)/2
A = 75/2 × 1/2
A = 75 × 1/2 × 2
A = 75/4
Thus,
- Acceleration is 75/4 m/s²
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