Question

find the acceleration of a body moving in a Time interval of 5 minutes for 47 km​

Answer 1

Acceleration is the rate of change of velocity.

It is given by the formula,

Acceleration(a) = displacement/time^2

                         = s/t^2

Given s = 47km

Time = 5 minutes = 1/12 hrs

Acceleration = 47/(1/144) = 47 X 144 m/s^2

                         = 6768m/s^2

Answer 2

Answer:

It is given by the formula,

Acceleration(a) = displacement/time^2

= s/t^2

Given s = 47km

Time = 5 minutes = 1/12 hrs

Acceleration = 47/(1/144) = 47 X 144 m/s^2

= 6768m/s^2