Question

find the acceleration of a body whose velocity increases from 11 metre per second to 33 metre per second in 10 seconds what is the answer of this question​

Answer 1

Answer:

$a = \frac{33 - 11}{10} \\ \\ = \frac{22}{10} \\ \\ = 2.2 \: m {s}^{ - 2}$

Answer 2

Answer:

initial velocity u = 11 m/s

final velocity v = 33 m/s

time taken t= 10 s

acceleration = v-u/t

= 33 - 11/10

= 22/10

= 2.2 m/s-²

hope it helps u out....