Question

find the acceleration of a body whose velocity increases from 11m/s to 33m/s in 10 seconds with data

Answer 1

Answer:

We know, a = v₂ - v₁ / t

Here, (v₂-v₁) = 33 - 11 = 22 m/s

t = 10 s

Substitute their values,  

a = 22/10

a = 2.2 m/s²

In short, Your Answer would be 2.2 m/s²

Hope this helps!

Explanation:

Answer 2

Answer:

data:-

a=?

vi=11m/s

vf=33m/s

t=10sec

solution:-

a=vf-vi/t

a=33-11/10

a=22/10

a=2.2m/sec²