Question

find the acceleration of a car and its displacement from the following observation time 3:15pm speed (in km/h) 26​

Answer 1

Explanation:

equations of motion can be used tobsolve these problems

Answer 2

Answer:

Explanation:

u=26km/h = 26*5/18 = 10m/sec

v=60km/h = 60*5/18 = 50/3m/sec

t = 30 minute = 0.5 Hours

v=u+at

50/3=10+a*0.5

a=200/15m/sec^2

Displacement can be find out from equation of motion:

v^2= u^2+2*a*S

(50/3)^2 = 10^2 + 2*200/15*S

13500+3600S = 37500

3600S = 37500-13500

S = 24000/3600

S = 21.5km