find the acceleration of a car and its displacement from the following observation time 3:15 p.m. speed 26 kilometre per hour
Answers
Answer:
Car speed is 26 (km/h) at 3:15 PM and 60 (km/h) at 3:45 PM.
To Find:
Find the acceleration of a car and its displacement cover during observation of time.
Solution:
Time (t) = 30 minute = 0.5 Hours
Acceleration can be find out from equation of motion:
On simplify:
Displacement can be find out from equation of motion:
On simplify, we get:
Displacement = s = 21.5 km
Explanation:
Given:
Car speed is 26 (km/h) at 3:15 PM and 60 (km/h) at 3:45 PM.
To Find:
Find the acceleration of a car and its displacement cover during observation of time.
Solution:
\mathbf{Initial \ speed\ (u)= 26 \ \ \dfrac{km}{h}}Initial speed (u)=26 hkm
\mathbf{Final \ speed\ (v)= 60 \ \ \dfrac{km}{h}}Final speed (v)=60 hkm
Time (t) = 30 minute = 0.5 Hours
Acceleration can be find out from equation of motion:
\mathbf{v=u+at}v=u+at
\mathbf{60=26+0.5\times a}60=26+0.5×a
On simplify:
\mathbf{acceleration = a = 68 \ \dfrac{km}{h^{2}}}acceleration=a=68 h2km
Displacement can be find out from equation of motion:
\mathbf{v^{2}=u^{2}+2\times a\times s}v2=u2+2×a×s
\mathbf{60^{2}=26^{2}+2\times 68\times s}602=262+2×68×s
On simplify, we get:
Displacement = s = 21.5 km