Question

find the acceleration of a motor bike moving along a straight path that changes its velocity from 90KM/hr to complete rest of 8 seconds​

Answer 1

Answer:

Answer is in the image..

Hope it's useful..

Answer 2

Answer:

Given : Mass of the motorcar, M=1200kg

Initial velocity of the car, u=90 km/h=25 m/s (∵1km/h=

18

5

m/s)

Final velocity of the car, v=18 km/h=5 m/s

Time taken t=4 s

ΔP=mv−mu

ΔP=1200×5−1200×25=−24000 kg m/s

v=u+at

5=25+a×4

⟹a=−5 m/s

2

(-ve shows retardation)

∣F∣=m∣a∣=1200×5=6000 N