find the acceleration of a truck which is initially moving with the speed of 40 kilometre per hour and then comes to rest in 5 seconds
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Initial velocity =40km/hr=>40x5/18=>11.11m/s
Final velocity =0km/hr=>0m/s
Time taken=5 sec
WKT:
V=u + at (or) a=(v-u) /T
a=0-40/5
a= - 40/5
a= - 8m/s^2...
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1
Explanation:
Answer refer in Attachment
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