Question

find the acceleration of particle if s=2t³-3t²+2t+2​

Answer 1

The position of a particle moving along x-axis is given by

x=(−2t3+3t2+5)m

Velocity, v=dtdx=0

−6t2+6t=0. . . . . . .(1)

6t(−t+1)=0

−t+1=0

t=1sec

Acceleration, a=dtdv

a=−12t+6

a∣t=1sec=−12×1+6

a∣t=1sec=−6m/s2