Find the acceleration of the block with 2 forces in from both side on is 20N nd second is 10N
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Answer:
a=1
Explanation:
we know that
F=MA
given: force= 20N and 10N
LET MASS BE M
so ATQ
F=MA
20= MA
20/A=M ............(1)
F=MA
10=MA
10/A=M ...............(2)
SOLVING (1) AND (2)
F=MA
10+20=20/A+10/A
30= 30/A
30/30=A
A=1m/s²
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