Question

Find the acceleration of the body of mass 3 kg, and express it in terms of unit vector, when acted upon
by forces: F1 = 4i + 4√3j, F2 = -5i+5√3j, F3 = 6√3i-6j, F4 = -3i-3j.

Answer 1

Answer:

let resultant force be F=F1+F2+F3+F4

$= (6 \sqrt{3} - 4)i + (9 \sqrt{3} - 9)j$

Explanation:

acceleration =net force /mass

a=F/m

a=

$\frac{2}{3} (3 \sqrt{3} - 2)i +3( \sqrt{3} - 1)j$

is the acceleration of the body in vector form.