Question

find the acceleration produced by a force of 40 N on an object of mass 5 kg​

Answer 1

$\boxed{\huge{\bf{\star{AnswEr \:-:}}}}$

$\sf{\star{Acceleration\:Produced=\:9\:m/s²}}$

$\large{\bf{\star{Given\:-:}}}$

$\sf{\Rightarrow{Applied\:Force-:40 \:N \:(n = \:newton)}}$

$\sf{\Rightarrow{On\:an\:object\:of\:mass\:-:5 \:kg \:(kg = \:kilo\:gram)}}$

$\large{\bf{\star{To\:Find\:-:}}}$

$\sf{\Rightarrow{Produced\:Acceleration}}$

$\large{\bf{\star{Solution \:-:}}}$

$\sf{\star{As,\:we\:know\:that,}}$

$\sf{\star{F=M \times A}}$

$\sf{Here,}\\\\{\sf{F =\:Force=\:40\:N}}\\{\sf{M =\:Mass\: 5\:kg}}\\{\sf{A =\:Acceleration\:??}}$

$\rightarrow{\sf{40 = 5 \times A }}$

$\rightarrow{\sf{A= \frac{40}{5}}}$

$\rightarrow{\sf{A= 9}}$

$\large{\bf{Hence,}}$

$\sf{\star{Acceleration\:Produced=\:9\:m/s²}}$

$\large{\bf{Let's\:Know\:more,}}$

$\sf{\star{Force\:-:\:A\:Force\:is\:a\:push\:or\:pull\:that}}\\{\sf{tends\:an\:object\:to\:move.}}\\{\sf{The\:SI\:Unit\:of\:force\:is \:N\:(n =\:newton)}}$

$\sf{Formula\:to\:find\:Force \:-:}$

$\sf{\star{F=M \times A}}$

$\sf{Here,}\\\\{\sf{F =\:Force}}\\{\sf{M =\:Mass}}\\{\sf{A =\:Acceleration}}$

$\sf{\star{Acceleration \:-:\:An\:Acceleration \:is\:a\:rate\:of}}\\{\sf{change\:in\:velocity.}}\\{\sf{The\:SI\:Unit\:of\:Acceleration \:is \:m/s²\:(m/s² =\:metre\:per\:second\:square)}}$

$\sf{Formula\:to\:find\:Acceleration \:-:}$

$\sf{\star{A= \frac{v-u}{t}}}$

$\sf{Here,}\\\\{\sf{V =\:Final\:Velocity}}\\{\sf{U =\:Initial\:Velocity}}\\{\sf{A =\:Acceleration}}$

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