Question

Find the acceleration produced on a mass of 250 kg by a force of 1250 N. Find the distance travelled from rest in 10 seconds.
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Answer 1

Given:-

• Mass of body = m = 250 kg
• Force = 1250 N
• Initial velocity = u = 0 m/s
• Time = t = 10 s

To find:-

• Acceleration = a
• Displacement = s

Answer:-

Finding acceleration:-

From Newton's second law of motion, we know that,

F = ma

where,

• F is force
• m is mass
• a is acceleration

So, putting available values given in the question,

1250 = 250 * a

→ a = 1250/250

→ a = 5 m/s² Ans

Finding displacement:-

From second equation of motion, we know that,

s = ut + (1/2)at²

where,

• s is displacement
• u is initial velocity
• t is time
• a is acceleration

So, putting available values given in the question,

s = (0 * 10) + [(1/2) * 5 * 10²]

→ s = 1/2 * 5 * 10 * 10

→ s = 5 * 5 * 10

→ s = 250 m Ans

Answer 2

Answer:

Given :-

• A mass of 250 kg by a force of 1250 N and its is travelled from rest in 10 seconds.

To Find :-

• What is the acceleration and the distance travelled.

Formula Used :-

To find acceleration we know that,

✪ a = F/m ✪

where,

• a = Acceleration
• F = Force
• m = Mass

To find distance travelled we know that,

★ s = ut + ½ at² ★

where,

• s = Distance travelled
• u = Initial velocity
• t = Time
• a = Acceleration

Solution :-

To find acceleration,

Given :

• Force = 1250 N
• Mass = 250 kg

According to the question by using the formula we get,

↦ a = F/m

↦ a = 1250/250

↦ a = 125/25

➠ a = 5 m/s²

∴ The acceleration is 5 m/s² .

Again, we have to find the distance travelled,

Given :

• Initial velocity = 0 m/s
• Time = 10 seconds
• Acceleration = 5 m/s²

According to the question by using the formula we get,

⇒ s = ut + ½ at²

⇒ s = 0(10) + ½ × (5)(10)²

⇒ s = 0 × 10 + ½ × 5 × 100

⇒ s = 0 + ½ × 500

⇒ s = 0 + 250

➦ s = 250 m

∴ The distance travelled is 250 m .