Math, asked by rct19562, 1 month ago

Find the accumulated value of the deposit $2500 made in simple interest for 3.5 years at 5% rate of interest per year.
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Answers

Answered by ItzFadedGuy
48

{\huge{\underline{\bf{Solution:}}}}

\begin{gathered} \\ \end{gathered}

Given:

  • Principal = $2500
  • Time in years = 3.5
  • Rate of interest = 5%

\begin{gathered} \\ \end{gathered}

To find:

\begin{gathered} \\ \end{gathered}

  • Accumulated Value

\begin{gathered} \\ \end{gathered}

Solution:

\begin{gathered} \\ \end{gathered}

To find the simple interest, we use the formula:

\multimap \: \boxed{ \sf Simple\:Interest = \dfrac{PRT}{100}}

Where,

  • P = Principle
  • R = Rate of Interest
  • T = Time (years)

\begin{gathered} \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{PRT}{100} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{2500 \times 5 \times 3.5}{100} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = \dfrac{25 \cancel{00} \times 5 \times 3.5}{1 \cancel{00}} \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Simple\:Interest = 25 \times 5 \times 3.5 \\ \\ \end{gathered}

\colon \implies\underline{ \boxed{ \bf{ \red{Simple\:Interest = 437.50}}}} \: \bigstar

\begin{gathered} \\ \end{gathered}

Accumulated value is nothing but Amount. Hence, to find Amount, we use the formula:

\begin{gathered} \\ \end{gathered}

\multimap \: \boxed{ \sf Amount = P+I}

Where,

  • P = Principal
  • I = Simple Interest

\begin{gathered} \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Amount = P+I \\ \\ \end{gathered}

\begin{gathered} \colon \longrightarrow \sf \: Amount = 2500+437.50 \\ \\ \end{gathered}

\colon \implies\underline{ \boxed{ \bf{ \green{Amount= 2937.50}}}} \: \bigstar

Hence, the accumulated value is 2937.50

Answered by OtakuSama
41

Question:-

Find the accumulated value of the deposit $2500 made in simple interest for 3.5 years at 5% rate of interest per year.

Required Answer:-

Given:-

 \sf{ \rightarrow{Principle \: amount  \: \bold{P} =  \$2500}}

 \sf{ \rightarrow{ Time \: \bold{T} = 3.5 years}}

 \sf{ \rightarrow{rate \: of \: intersest  \: \bold{R} = 5\%}}

To Find:-

 \sf{ \rightarrow{accumulated \: value \:  \bold{a}}}

Solution:-

As we know that,

 \underline{ \boxed{ \rm{ \blue{Simple \: interest  \: \bold{I} = PTR}}}}

Substituting the values :-

 \sf{ \bold{Simple \: Interest } = 2500 \times 3.5 \times 5\%}

 \\  \sf{ \implies{ \bold{Simple \: Interest} = 2500 \times 3.5 \times  \frac{5}{100} }}

\\  \sf{ \implies{ \bold{Simple \: Interest} =  \pink{437.5 }}}

Therefore, simple interest = $437.5

Again,

The accumulated value means the amount.

We know that,

 \underline{ \boxed{ \rm{ \blue{Amount \: \bold{A} = P + I}}}}

Substituting the values:-

 \sf{ \bold{Amount} = 2500 + 437.5}

 \\ \sf{ \implies{ \bold{Amount} =  \orange{\boxed{2937.5}}}}

Therefore, the accumulated value is $2937.5

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