find the actual lengths
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Hello Friend !
Here's is the answer to your query !
Hope it helps :-
Since the point of intersection of tangent and radius makes angle .
Therefore by using pythagorus theorem :
(x-1)² + (x+3)² = (x+1)²
⇒ (x² - 2x + 1) + (x² + 6x + 9) = x² + 2x + 1
⇒ 2x² + 4x + 10 = x² + 2x + 1
⇒ x² + 2x + 9 = 0
⇒ x² + 2x + 1 - 1 + 9 = 0
⇒ (x + 1)² = -8
⇒ (x + 1) = 2√2
⇒ x = 2√2 - 1
This is your answer.
Hope this cleared your doubt !
Here's is the answer to your query !
Hope it helps :-
Since the point of intersection of tangent and radius makes angle .
Therefore by using pythagorus theorem :
(x-1)² + (x+3)² = (x+1)²
⇒ (x² - 2x + 1) + (x² + 6x + 9) = x² + 2x + 1
⇒ 2x² + 4x + 10 = x² + 2x + 1
⇒ x² + 2x + 9 = 0
⇒ x² + 2x + 1 - 1 + 9 = 0
⇒ (x + 1)² = -8
⇒ (x + 1) = 2√2
⇒ x = 2√2 - 1
This is your answer.
Hope this cleared your doubt !
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