find the acute angle a and b , a>b, if sin (a+2b)=root3/2 and cos (a+4b)=0.
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first take cos(a+4b)=0
cos(a+4b)=cos90
(a+4b)=90
now take sin(a+2b)=√3/2
sin(a+2b)=sin60
(a+2b)=60
now subtract eq1 and eq2
we will get b= 15
putting the value of in eq2
we get a=30
cos(a+4b)=cos90
(a+4b)=90
now take sin(a+2b)=√3/2
sin(a+2b)=sin60
(a+2b)=60
now subtract eq1 and eq2
we will get b= 15
putting the value of in eq2
we get a=30
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