Find the acute angle between the line 3x+2y+4=0 and 2x-3y-7=0
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Given lines are,
3x + 2y + 4 = 0
2x - 3y - 7 = 0
Slope of a line of the form ax + by + c = 0 is - a/b
Slope of 3x + 2y + 4 = 0 is - 3/2
Slope of 2x - 3y - 7 = 0 is - ( 2/-3) = 2/3
Product of slopes is,
-3/2 × 2/3 = - 1.
Therefore, The lines are perpendicular and The angle between the lines is 90°.
- Product of slopes of perpendicular lines is always -1
- Parallel lines have same Slope.
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Answer:
-1 parallel lines have same slope.
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