Question

Find the acute angle between y = x + 3 and y = -3x + 5 to the nearest degree.

Answer 1

Answer:

≈ 63°

Step-by-step explanation:

tanβ = | ($m_{2}$ - $m_{1}$) / (1 + $m_{1} m_{2}$) |

y = x + 3 ⇒ $m_{1}$ = 1

y = - 3x + 5 ⇒ $m_{2}$ = - 3

tanβ = (- 3 - 1) ÷ (1 - 3) = 2

β ≈ 63°