Question

find the acute angle θ such that cos 27°+cos 33°=√3cos θ​

Answer 1

Answer:

$3^{0}$

Step-by-step explanation:

Formula :    $cosA +cosB = 2 cos (\frac{A +B}{2}) cos (\frac{A-B}{2} )$

Now ,  $cos 27^{0} + cos33^{0} = \sqrt{3}$ cos∅

   =>   $2 cos (\frac{27^{0}+33^{0}}{2})cos(\frac{33^{0}-27^{0}}{2} ) = \sqrt{3}$cos∅

   =>   $2 cos 30^{0} cos3^{0}= \sqrt{3}$cos∅

   =>  cos∅ = $cos3^{0}$

   =>    ∅ = $3^{0}$