find the acute angle theta such that 5tan square theta + 3 = 9 sec theta
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Answer:
θ = 60°
Step-by-step explanation:
Find the acute angle theta such that 5tan square theta + 3 = 9 sec theta
5Tan²θ + 3 = 9Secθ
Using
Sec²θ = Tan²θ + 1
=> Tan²θ = Sec²θ - 1
5(Sec²θ - 1) + 3 = 9 Secθ
=> 5Sec²θ - 9Secθ - 2 = 0
=> 5Sec²θ - 10Secθ + Secθ - 2 = 0
=> 5Secθ(Secθ - 2) + 1(Secθ - 2) = 0
=> (5Secθ + 1)(Secθ - 2) = 0
Secθ = -1/5 => Cosθ = -5 (not possible)
Secθ = 2 => Cosθ = 1/2 => θ = 60°
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