Find the acute angls A and B satisfying
tan(A+B)=√3 and cosec(A-B)=2
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Step-by-step explanation:
tan(A+B) = √3
tan(A+B) = tan60°
A + B = 60° ------ (1) Cosec(A-B) = 2
Cosec(A-B) = Cosec30°
A - B = 30° -------(2)
equation (1) + (2) Se
2A = 90°
A = 45°
B = 15°
Answered by
1
acute angles
A=45°
B=15°
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