find the addition of all the outer angles of a star
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A star comprises of two triangles with the angles of the triangle forming the outer angles of a star.
We know that the sum of angles of a triangle is 180 degrees so the outer angles of a star = 2 x 180 degrees
= 360 degrees
Hope that helps!!
We know that the sum of angles of a triangle is 180 degrees so the outer angles of a star = 2 x 180 degrees
= 360 degrees
Hope that helps!!
Answered by
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In the center is a 5-sided regular polygon (a regular
pentagon). The sum of the interior angles of a polygon
is gotten by the formula:
SUM OF INTERIOR ANGLES = (NUMBER OF SIDES - 2) * 180°
For a 5-sided polygon (pentagon) this is (5-2)*180° = 3*180°=540°
Since all 5 angles of a regular pentagon are equal, each interior angle of the regular pentagon is 540/5=108
Its suppplement is found by subtracting 180°-108°=72°. We'll mark it 72°:
That 72° angle is one of the base angles of an isosceles triangle. So we'll mark the other base angle 72° also.
Now we can find the angle at the top point of the star by adding the two equal base angles and subtracting from 180°. 72° + 72° = 144° 180° - 144° = 36° So each point of the star is 36°
SUM OF INTERIOR ANGLES = (NUMBER OF SIDES - 2) * 180°
For a 5-sided polygon (pentagon) this is (5-2)*180° = 3*180°=540°
Since all 5 angles of a regular pentagon are equal, each interior angle of the regular pentagon is 540/5=108
Its suppplement is found by subtracting 180°-108°=72°. We'll mark it 72°:
That 72° angle is one of the base angles of an isosceles triangle. So we'll mark the other base angle 72° also.
Now we can find the angle at the top point of the star by adding the two equal base angles and subtracting from 180°. 72° + 72° = 144° 180° - 144° = 36° So each point of the star is 36°
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Anonymous:
thanks
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