Find the additive identity of -3+(-2)÷2
Answers
Answered by
1
Answer:
keep smiling.....
Step-by-step explanation:
For a number
a
, it's multiplicative inverse
b
is such that
a
⋅
b
=
1
which is the multiplicative identity.
For a number
a
, it's additive inverse
c
would be such that
a
+
c
=
0
where
0
is additive identity.
Thus, for
a
=
−
8
It's additive inverse be
c
.
Then
−
8
+
c
=
0
Now, adding
8
to both sides,
c
=
8
.
Let the multiplicative inverse be
b
.
Then
a
⋅
b
=
1
⇒
−
8
⋅
b
=
1
Multiplying both sides with
−
1
8
b
=
−
1
8
Answered by
0
Answer:
-3+(-2)÷2
-5÷2
=-0.115
Similar questions