Question

Find the additive inverse of -1/-3​

Answer 1

Given :- Find the additive inverse of -1/-3 .

Solution :-

we know that,

• The additive inverse of a number is the number that, when added to given number gives result zero.

so, let additive inverse of -1/-3 is x .

then,

→ (-1)/(-3) + x = 0

→ 1/3 + x = 0

taking (1/3) to RHS side and changing the sign ,

→ x = (-1/3) (Ans.)

Hence, the additive inverse of -1/-3 will be (-1/3) .

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Answer 2

Given:

$\dfrac{ - 1}{ - 3}$

To find:

Additive inverse of the given rational number.

Solution:

• In Additive Inverse Property, the sum of any number with its inverse is always zero.
• The additive inverse is also called the opposite of the number or negation of the number.

For example:

Additive inverse of 6 is -6

=> 6 + (-6)

=> 0

Now, let's see what's the additive inverse of a given rational number:

$= > \dfrac{ - 1}{ - 3} = \dfrac{1}{3}$

The additive inverse of :

$= > \dfrac{1}{3} = - ( \dfrac{1}{3} ) = \dfrac{ - 1}{3}$

Hence, the required answer is:

$= > \dfrac{ - 1}{3}$