Question

find the aera of a square whose one slide 113cm

Answer 1

Answer:

Side of square =7.5cm

Area =(7.5)

2

=56.25sqcm

Answer 2

$\color{skyblue}{\bigstar \large\underline{\boxed{\bf\pink{Question:-}}}}$

$\tt\red{Find \: the \: aera \: of \: a \: square \: whose \: one \: slide \: 113cm}$

$\color{skyblue}{\bigstar \large\underline{\boxed{\bf\pink{Answer:-}}}}$

D I A G R A M :

$\begin{gathered} \pink{\begin{gathered} \sf{113 \:cm}\huge\boxed{ \begin{array}{cc} \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \ \\ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{113 \: cm} \end{gathered}}\end{gathered}$

Given :-

• The side of square = 113 cm

To Find :-

• The area of Square

Formula :-

$\dag{ \boxed{ \sf \red{{Area_{(Square)} = side^{2} }}}}$

$\bf \bigstar \: Finding \: the \: area \: of \: Square$

$\sf \orange{ \mapsto \: Area \: of \: Square =(113cm )^{2}}$

$\sf \blue{ \mapsto \: Area \: of \: Square =113 \times 113}$

$\sf \purple{\mapsto \: Area \: of \: Square =12769 \: cm^{2} }$

$\bf \red{know \: more}$

$\begin{gathered}\begin{gathered} \small\begin{gathered}\bigstar \: \bf\underline{More \: Useful \: Formulae } \: \bigstar \\ \begin{gathered}{\boxed{\begin{array} {cccc}{\sf{{\leadsto TSA \: of \: cube \: = \: 6(side)^{2}}}} \\ \\{\sf{{\leadsto LSA \: of \: cube \:= \: 4(side)^{2}}}} \\ \\{\sf{{\leadsto Volume \: of \: cube \: = \: (side)^{3}}}} \\ \\ {\sf{{\leadsto Diagonal \: of \: cube \: = \: \sqrt(l^{2} + b^{2} + h^{2}}}} \\ \\ {\sf{{\leadsto Perimeter \: of \: cube \: = \: 4(l+b+h)}}} \\ \\ {\sf{{\leadsto CSA \: of \: sphere \: = \: 2 \pi r^{2}}}} \\ \\ {\sf{{\leadsto SA \: of \: sphere \: = \: 4 \pi r^{2}}}} \\ \\{\sf{{\leadsto TSA \: of \: sphere \: = \: 3 \pi r^{2}}}} \\ \\ {\sf{{\leadsto Diameter \: of \: circle \: = \: 2r}}} \\ \\ {\sf{{\leadsto Radius \: of \: circle \: = \: \dfrac{d}{2}}}} \\ \\ {\sf{{\leadsto Volume \: of \: sphere \: = \: \dfrac{4}{3} \pi r^{3}}}} \\ \\ {\sf{{\leadsto Area \: of \: rectangle \: = \: Length \times Breadth}}} \\ \\ {\sf{{\leadsto Perimeter \: of \: rectangle \: = \:2(length+breadth)}}} \\ \\{\sf{{\leadsto Perimeter \: of \: square \: = \: 4 \times sides}}}\end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$