Question

Find the age of Aishwarya and her daughter Aaradhya, if the sum and difference of the arrangements of their ages is 5/40 and 3/40 respectively.

Answer 1

The age of Ashiwarya is  40 years

The age of Aaradhya is 10 years

Step-by-step explanation:

Given as :

The sum of ages of Aishwarya and Aaradhya = $\dfrac{5}{40}$

The difference of ages of Aishwarya and Aaradhya = $\dfrac{3}{40}$

Let The Age of Aishwarya = x years'

Let The age of Aaradhya = y  years

According to question

sum of ages of Aishwarya and Aaradhya = $\dfrac{5}{40}$

i.e  x + y = $\dfrac{5}{40}$             ...............1

And

The difference of ages of Aishwarya and Aaradhya = $\dfrac{3}{40}$

i.e   x - y  = $\dfrac{3}{40}$               .............2

Solving eq 1 and eq 2

( x + y ) + ( x - y ) = $\dfrac{5}{40}$ + $\dfrac{3}{40}$

Or, 2 x = $\dfrac{8}{40}$

Or,  2 x = $\dfrac{1}{5}$

i.e   x = $\frac{1}{10}$  

Now, put the value of x in eq 1

x + y = $\dfrac{5}{40}$

Or,  y = $\dfrac{5}{40}$  - $\frac{1}{10}$

Or,  y = $\dfrac{5-4}{40}$

i.e y = $\dfrac{1}{40}$

So, The age of Ashiwarya = 40 years

The age of Aaradhya = 10 years

Hence, The age of Ashiwarya is  40 years

And       The age of Aaradhya is 10 years         Answer